Method One, use QQ computer housekeeper
1. We found "computer clinic" in "QQ computer housekeeper" as shown in the following picture.
2. Then we clicked on the "Tencent zone" above, and then we clicked on the top search input "QQ installation" as
0xb8000 32 K 32 K 0x00000000 32 K 34 (0x022) 0x00000001 T 80x60 8x8 0xb8000 32 K 32 K 0x00000000 32 k 37 (0x025) 0x00000003g 320x240x8 4 8x8 0xa0000 64 K 64 K 0x00000000 256k112 (0x070) 0x00000000 T 80x43 8x8 0xb8000 32 K 32 K 0x00000000 32k113 (0x071) 0x00000001 T 80x43 8x8 0xb8000 32 K 32 K 0x00000000 32k257 (0x101) 0x0000000f g 640x480X8 1 8x16 0xa0000 64 K 64 K 0xc0000000 7872k259 (0x103) 0x0000000f g
32 k 32 (0x020) 0x00000001 T 80x30 8x16 0xb8000 32 k 32 k 0x00000000 32 k 34 (0x022) 0x00000001 T 80x60 8x8 0xb8000 32 k 32 k 0x00000000 32 k 37 (0x025) 0x00000003G 320x240x8 V 8x8 0xa000 0 64 k 64 k 0x00000000 256k112 (0x070) 0x00000000 T 80x43 8x8 0xb8000 32 k 32 k 0x00000000 32k113 (0x071) 0x00000001 T 80x43 8x8 0xb8000 32 k 32 k 0x00000000 32k257 (0x101) 0x0000000f G 640x480x8 P 8x16 0xa0000 64 k 64 k 0x80000000 300k259 (0x103)
For a given 32-bit integer, write a function. If this number is positive, 1 is returned. If it is negative,-1 is returned, if it is set to zero, zero is returned, and no condition is required to judge the branch jump statement. Here, a slight extension is provided, indicating the corresponding unsigned 32-bit integer. The solution is to separate the signed bits and values. For a 32-bit integer, the signed bits are shifted to 31 To Get A. If it is not a negative number, a = 0x00000000; otherwise,
mov edx, 0xf
08048079 B998900408 mov ecx, 0x8049098
0804807E bb0000000 mov ebx, 0x1
08048083 B804000000 mov eax, 0x4
08048088 CD80 int 0x80
0804808A BB00000000 mov ebx, 0x0
0804808F b80000000 mov eax, 0x1
08048094 CD80 int 0x80
The first column of the output information is the address code corresponding to the command. It can be used to set the breakpoint during program execution:
Ald> break 0x08048088
Breakpoint 1 set for 0x08048088
After the breakpoint is set, run the run Command to r
world character gb2312 is the old national standard, does not support traditional Chinese GBK is not the national standard, but supports traditional Chinese character gb18030 is the new national standard, it also supports traditional Chinese characters big-5 and traditional Chinese charactersISO-8859-1, does not support Chinese characters, the United States and other Latins are commonly used in this encodingExample:Public class encodingtest01 {public static void main (string [] ARGs) throws exc
Reference Online article: http://www.freebuf.com/articles/system/6388.htmlAccording to the article, the dynamic injection of code, that is, a running process, without restarting the implementation of the code is not within the original program.My lab Environment:Ubuntu 14.10 System1.Makefile Compilation:All:Gcc-g-wall Dynlib.c-fpic-shared-o libdynlib.soGCC app.c-g-o app-ldynlib-l./Gcc-wall injection.c-c-O INJECTION.OClean:Rm-f libdynlib.so2. My experiment records:GDB) Call Open ("INJECTION.O", 2
to the 1th element.
So, what happens to an array element as a reference. Referring to the 1th feature mentioned above, references are simply labels that need to be manually bound to an object (address area). When initializing a reference in an array, it is not guaranteed that the object bound by the logically contiguous reference element is also physically contiguous.
As an example:
If the reference array is legitimate and the compilation can be passed, then, according to syntax, the definition
1 0x00000001 the incorrect function.2 The 0x00000002 system could not find the specified file.3 The 0x00000003 system could not find the specified path.4 0x00000004 system cannot open file.5 0x00000005 denied access.6 0x00000006 Invalid code.7 0x00000007 Storage Control block has been destroyed.8 0x00000008 storage space is not sufficient to handle this instruction.9 0x00000009 Storage Control block address is invalid.0x0000000A environment is not correct.One 0x0000000b attempt to load a malform
This article describes how to obtain a list of sensors supported by your Android device.Currently, Android 4.4 (API level 19) supports the following sensors:Type_accelerometer Accelerometer, Unit m/s2, measurement of the accelerometer type values (sensors type) applied to the device x, Y, Z axes: 1 (0x00000001) Type_ambient_ Temperature temperature sensor, Unit is ℃ sensor type value (sensors type): (0x0000000d) Type_game_rotation_vector game action sensor, no electromagnetic interference affect
Addition operations without addition, subtraction, multiplication, division, and addition operations
1 int add (int a, int B) {2 char * c; 3 c = (char *) a; 4 return (int) c [B]; 5}
Based on the address, let the compiler calculate it for you. First, force convert a to the address, and then find the address headed by c. The offset is the address of B, that is, the value of a + B.
For example, a = 5, B = 10
C = (char *) a. The address of c is 0x00000005.
C [B] is the address offset siz
again.0x0012f434 0012f0000010300ad 00000063In this case, I1 and I2 are0012f440 010300ad test_console.class1.main ()Locals:0x0012f444 = 0x0000000f -- 150x0012f440 = 0x0000007f -- 127
We can exit the ref_out method, and the Register status is
EBP = 0012f133 (this value is the value of the address indicated by EBP when the ref_out method is executed) ESP = 0012f440 EIP = 010300ad
Through the above careful analysis, you should have understood why th
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